tracks and vias … 69
Routing differential pairs … 90
Length tuning … 90
Teardrops … 99
Backdrills and
hole post-machining (counterbores/countersinks) … 102
Graphics and text … 106
Rule areas (keepouts) … 128 connection width: 0 mm
Minimum annular width: 0.075 mm
Minimum via diameter: 0.45 mm
Copper to
hole clearance: 0.2 mm
Copper to edge clearance: 0.372 mm
Maximum allowed deviation: 0.005 filling can be slow when < 0.005 mm. | | Holes | Minimum drill size: 0.3 mm Hole to hole clearance: 0.25 mm | Zone Fill Strategy Allow fillets/chamfers outside zone outline Minimum 0 码力 |
327 页 |
10.81 MB
| 1 月前 3 Stackup Board Finish Solder Mask/Paste | Width | | Diameter | Hole | | Width | Gap | Via Gap |
| 0.3 mm | 0.45 either the Schematic or Board Setup dialogs.
Name
Clearance
Track Width
Via Size
Via Hole
μVia Size
uVia Hole
DP Width
DP Gap
POWER
0.15 mm
0.4 mm
0.8 mm
0.4 mm
0.3 mm
0.1 mm
0.2 mm
0.25 mm
Default needs to remain unsoldered in a specific design, or you may wish to move the location of a through-hole pad for an axial-lead resistor in order to fit a specific design.
NOTE
By default, the position of 0 码力 |
233 页 |
7.72 MB
| 1 月前 3 | | | | | | |
| Pre-defined Sizes | Hole clearance violation: | Error | Warning | Ignore | | | | RulesHole size out of range: | Error | Warning | Ignore | | | | | | |
| Violation Severity | Micro via hole size out of DIP:DIP-14_W7.62mm_LongPads | ☐ |
| Library Description | 14-lead though-hole mounted DIP package | ☐ |
| Keywords | THT DIP DIL PDIP 2.54mm 7.62mm 30 0 码力 |
205 页 |
6.78 MB
| 2 年前 3 | | | | | | |
| Pre-defined Sizes | Hole clearance violation: | Error | Warning | Ignore | | | | RulesHole size out of range: | Error | Warning | Ignore | | | | | | |
| Violation Severity | Micro via hole size out of DIP:DIP-14_W7.62mm_LongPads | ☐ |
| Library Description | 14-lead though-hole mounted DIP package | ☐ |
| Keywords | THT DIP DIL PDIP 2.54mm 7.62mm 30 0 码力 |
204 页 |
6.90 MB
| 2 年前 3 asking Idris to prove the hole $ r_{hs} $ using the command: p $ r_{hs} $ . Idris by default will show us the initial context. This looks as follows:
*Foo> :p rhs
Goal:
{ hole 0 }:
(n : Nat) ->
(m apply the intros tactic:
--Foo.rhs> intros
Other goals:
{ hole 2 }
{ hole 1 }
{ hole 0 }
Assumptions:
n : Nat
m : Nat
o : Nat
Goal:
{ hole 3 }:
plus n (plus m o) = plus (plus n m) o
### 2.3 Induction induction on to n:
--Foo.rhs> induction n
------------------- Other goals:
elim_SO
{ hole 2 }
{ hole 1 }
{ hole 0 }
------------------- Assumptions:
n : Nat
m : Nat
o : Nat
------------------- Goal: 0 码力 |
14 页 |
120.74 KB
| 2 年前 3 asking Idris to prove the hole $ r_{hs} $ using the command: p $ r_{hs} $ . Idris by default will show us the initial context. This looks as follows:
*Foo> :p rhs
Goal:
{ hole 0 }:
(n : Nat) ->
(m apply the intros tactic:
--Foo.rhs> intros
Other goals:
{ hole 2 }
{ hole 1 }
{ hole 0 }
Assumptions:
n : Nat
m : Nat
o : Nat
Goal:
{ hole 3 }:
plus n (plus m o) = plus (plus n m) o
### 2.3 Induction induction on to n:
--Foo.rhs> induction n
------------------- Other goals:
elim_SO
{ hole 2 }
{ hole 1 }
{ hole 0 }
------------------- Assumptions:
n : Nat
m : Nat
o : Nat
------------------- Goal: 0 码力 |
14 页 |
120.71 KB
| 2 年前 3 asking Idris to prove the hole $ r_{hs} $ using the command: p $ r_{hs} $ . Idris by default will show us the initial context. This looks as follows:
*Foo> :p rhs
Goal:
{ hole 0 }:
(n : Nat) ->
(m apply the intros tactic:
--Foo.rhs> intros
Other goals:
{ hole 2 }
{ hole 1 }
{ hole 0 }
Assumptions:
n : Nat
m : Nat
o : Nat
Goal:
{ hole 3 }:
plus n (plus m o) = plus (plus n m) o
### 2.3 Induction induction on to n:
--Foo.rhs> induction n
------------------- Other goals:
elim_SO
{ hole 2 }
{ hole 1 }
{ hole 0 }
------------------- Assumptions:
n : Nat
m : Nat
o : Nat
------------------- Goal: 0 码力 |
14 页 |
120.74 KB
| 2 年前 3 asking Idris to prove the hole $ r_{hs} $ using the command: p $ r_{hs} $ . Idris by default will show us the initial context. This looks as follows:
*Foo> :p rhs
Goal:
{ hole 0 }:
(n : Nat) ->
(m apply the intros tactic:
--Foo.rhs> intros
Other goals:
{ hole 2 }
{ hole 1 }
{ hole 0 }
Assumptions:
n : Nat
m : Nat
o : Nat
Goal:
{ hole 3 }:
plus n (plus m o) = plus (plus n m) o
### 2.3 Induction induction on to n:
--Foo.rhs> induction n
------------------- Other goals:
elim_SO
{ hole 2 }
{ hole 1 }
{ hole 0 }
------------------- Assumptions:
n : Nat
m : Nat
o : Nat
------------------- Goal: 0 码力 |
14 页 |
121.89 KB
| 2 年前 3 asking Idris to prove the hole $ r_{hs} $ using the command: p $ r_{hs} $ . Idris by default will show us the initial context. This looks as follows:
*Foo> :p rhs
Goal:
{ hole 0 }:
(n : Nat) ->
(m apply the intros tactic:
--Foo.rhs> intros
Other goals:
{ hole 2 }
{ hole 1 }
{ hole 0 }
Assumptions:
n : Nat
m : Nat
o : Nat
Goal:
{ hole 3 }:
plus n (plus m o) = plus (plus n m) o
### 2.3 Induction induction on to n:
--Foo.rhs> induction n
------------------- Other goals:
elim_SO
{ hole 2 }
{ hole 1 }
{ hole 0 }
------------------- Assumptions:
n : Nat
m : Nat
o : Nat
------------------- Goal: 0 码力 |
14 页 |
120.52 KB
| 2 年前 3
|