Experiment 2: Logistic Regression and Newton's Method
Experiment 2: Logistic Regression and Newton’s Method August 29, 2018 1 Description In this exercise, you will use Newton’s Method to implement logistic regression on a classification problem. 2 Data examples into your program and add the x0 = 1 intercept term into your x matrix. Before beginning Newton’s Method, we will first plot the data using different symbols to represent the two classes. In Matlab/Octave 1Note that it is not a must to perform this transformation, since both gradient ascent algorithm and Newton’s method can be applied to resolve maximization problems. 2 One approach to minimize the above0 码力 | 4 页 | 196.41 KB | 1 年前3Lecture 3: Logistic Regression
September 20, 2023 1 / 29 Lecture 3: Logistic Regression 1 Classification 2 Logistic Regression 3 Newton’s Method 4 Multiclass Classification Feng Li (SDU) Logistic Regression September 20, 2023 2 / 29 16 / 29 Newton’s Method Given a differentiable real-valued f : R → R, how can we find x such that f (x) = 0 ? ? ? 0 ?∗ Feng Li (SDU) Logistic Regression September 20, 2023 17 / 29 Newton’s Method ′(x1) ? ? 0 ?∗ ?" ?# ?", ? ?" ? Feng Li (SDU) Logistic Regression September 20, 2023 18 / 29 Newton’s Method (Contd.) Repeat the process and get a sequence of approximations x1, x2, x3, · · · ?0 码力 | 29 页 | 660.51 KB | 1 年前3Improving Our Safety With a Quantities and Units Library
becquerel; inline constexpr struct newton final : named_unit<"N", kilogram * metre / square(second)> {} newton; inline constexpr struct pascal final : named_unit<"Pa", newton / square(metre)> {} pascal; inline inline constexpr struct joule final : named_unit<"J", newton * metre> {} joule; inline constexpr struct watt final : named_unit<"W", joule / second> {} watt; inline constexpr struct coulomb final : named_unit<"C" becquerel; inline constexpr struct newton final : named_unit<"N", kilogram * metre / square(second)> {} newton; inline constexpr struct pascal final : named_unit<"Pa", newton / square(metre)> {} pascal; inline0 码力 | 207 页 | 6.93 MB | 5 月前3MoonBit月兔编程语言 现代编程思想 第十二课 案例:自动微分
4. Forward::var(10.0, false) * Forward::var(100.0, true) |> debug 23 案例:⽜顿迭代法求零点 1. fn example_newton[N : Number](x : N) -> N { 2. x * x * x + N::constant(-10.0) * x * x + x + N::constant(1.0) 3. } loop Forward::var(1.0, true) { // 迭代起点 4. x => { 5. let { value, derivative } = example_newton(x) 6. if abs(value / derivative) < 1.0e-9 { 7. break x.value // 精度⾜够,终⽌循环 8.0 码力 | 30 页 | 3.24 MB | 1 年前3Docker 从入门到实践 0.4
"/bin/bash" 30 minutes ago Exited (0) About a minute ago trusting_newton 98e5efa7d997 training/webapp:latest "python app.py" About an hour ago Exited (0) Docker —— 从入门到实践 35 导出和导入 可以使用 docker rm 来删除一个处于终止状态的容器。 例如 $sudo docker rm trusting_newton trusting_newton 如果要删除一个运行中的容器,可以添加 -f 参数。Docker 会发送 SIGKILL 信号给容器。 删除容器 Docker —— 从入门到实践 36 删除0 码力 | 179 页 | 2.27 MB | 1 年前3Scientific Unit Testing
com 1If I have seen further than others, it is by standing upon the shoulders of giants. -- Isaac Newton T. Winters and H. Wright, All Your Tests Are Terrible... CppCon 2015 Fedor Pikus, Back to Basics:0 码力 | 45 页 | 1.91 MB | 5 月前3机器学习课程-温州大学-08机器学习-集成学习
XGBoost - Why Does XGBoost Win “Every” Machine Learning Competition?[J], 2016. [11] Polyak B T . Newton's method and its use in optimization[J]. European Journal of Operational Research, 2007, 181(3):1086-10960 码力 | 50 页 | 2.03 MB | 1 年前3Exploration of Strongly-typed Units: A Case Study from Digital Audio
11, 1998 Cost $327.6 million Expected to reach Mars September 23, 1999 Pound-force-seconds vs newton-secondsWhat do units matter? … “is it supposed to make sound?”Not life and death, but audio bugs0 码力 | 106 页 | 5.66 MB | 5 月前3Docker 从入门到实践 0.9.0(2017-12-31)
"/bin/bash" 30 minutes ago Exited (0) About a minute ago trusting_newton 98e5efa7d997 training/webapp:latest "python app.py" About an hour ago Exited 115 删除容器 可以使用 docker container rm 来删除一个处于终止状态的容器。例如 $ docker container rm trusting_newton trusting_newton 如果要删除一个运行中的容器,可以添加 -f 参数。Docker 会发送 SIGKILL 信号给容器。 清理所有处于终止状态的容器 用 docker container0 码力 | 370 页 | 6.73 MB | 1 年前3Python 标准库参考指南 2.7.18
"Isaac Newton, physicist") >>> m.group(0) # The entire match 'Isaac Newton' >>> m.group(1) # The first parenthesized subgroup. 'Isaac' >>> m.group(2) # The second parenthesized subgroup. 'Newton' >>> >>> m.group(1, 2) # Multiple arguments give us a tuple. ('Isaac', 'Newton') 如果正则表达式使用了 (?P⋯) 语法,groupN 参数就也可能是命名组合的名字。如果一 个字符串参数在样式中未定义为组合名,一个IndexError 就 raise。 A moderately complicated example: >>> C["fig"] = "newton" >>> C["sugar"] = "wafer" >>> print C # generate HTTP headers Set-Cookie: fig=newton Set-Cookie: sugar=wafer >>> print C.output() # same thing Set-Cookie: fig=newton Set-Cookie: sugar=wafer 0 码力 | 1552 页 | 7.42 MB | 9 月前3
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