multi-page HTML and man page format doc/src/sgml/postgres-A4.pdf Build documentation in PDF format, with A4 pages doc/src/sgml/postgres-US.pdf Build documentation in PDF format, with US letter pages doc/src/sgml/postgres text[]); a | b | c 0 | a | {a0,b0,c0} 1 | b | {a1,b1,c1} 2 | c | {a2,b2,c2} 3 | d | {a3,b3,c3} 4 | e | {a4,b4,c4} 5 | f | {a5,b5,c5} 6 | g | {a6,b6,c6} 7 | h | {a7,b7,c7} 8 | i | {a8,b8,c8} 9 | j | {a9,b9,c9} using FOP, you can use one of the following commands, depending on the preferred paper format: • For A4 format: doc/src/sgml$ make postgres-A4.pdf • For U.S. letter format: doc/src/sqml$ make postgres-US

c5 86 c0 3c 6e b9 c7 fa 50 57 3d 0f 9b 8b 0b 3d 21 a7 bd 62 fc 5f b7 4e 21 d5 6f b5 27 57 68 ff 6e a4 b1 a0 51 06 f5 b2 11 cd 46 d8 be 3e ad a1 be 3d 9f e1 89 46 6c 99 e6 83 f3 82 d5 bb b4 bd d5 0c c5 35 b9 cd fe 05 5e 10 96 48 b6 4b bd 4e 91 29 c7 96 ef 9a 33 64 4f 52 9b 5d 09 46 83 09 a4 a2 09 f8 32 7f 7f 4c 0d a4 e0 f7 7b c3 08 79 96 fb 00 81 13 67 2b 7e 74 6a 66 15 60 03 19 28 f0 36 5a a2 42 13 3f 35 b9 cd fe 05 5e 10 96 48 b6 4b bd 4e 91 29 c7 96 ef 9a 33 64 4f 52 9b 5d 09 46 03 09 a4 a2 09 f8 32 7f 7f 4c 0d a4 e0 f7 7b c3 08 79 96 fb 00 81 13 67 2b 7e 74 6a 66 15 60 03 19 28 f0 36 5a a2 42 13 3f

a1|Function argument, return value| |x12 / a2|Function argument| |x13 / a3|Function argument| |x14 / a4|Function argument| |x15 / a5|Function argument| |x16 / a6|Function argument| |x17 / a7|Function argument| 补充说明：不使用条件码实现大位宽数据的加法 在 RV32I 中是通过 sltu 计算进位来实现的： add a0, a2, a4 # 加低 32 位: $ a_{0} = a_{2} + a_{4} $ sltu a2, a0, a2 # 若 $ (a2 + a4) < a2 $ 那么 $ a2' = 1 $ ，否则 $ a2' = 0 $ add a5, a1 is n, a3 points to a[0], a4 is i, a5 is j, a6 is x 0: 00450693 addi a3, a0, 4 # a3 is pointer to a[i] 4: 00100713 addi a4, x0, 1 # i = 1 Outer Loop: 8: 00b76463 bltu a4, a1, 10 # if i < n, jump

RV32I utilizando s1tu para calcular o carry-out: add a0, a2, a4 # add lower 32 bits: a0 = a2 + a4 sltu a2, a0, a2 # a2' = 1 if (a2 + a4) < a2, a2' = 0 otherwise add a5, a3, a5 # add upper 32 a1 is n, a3 points to a[0], a4 is i, a5 is j, a6 is x 0: 00450693 addi a3, a0, 4 # a3 é ponteiro para a[i] 4: 00100713 addi a4, x0, 1 # i = 1 Laço externo: 8: 00b76463 bltu a4, a1, 10 # se i < n, salta lw a6, 0(a3) # x = a[i] 14: 00068613 addi a2, a3, 0 # a2 é ponteiro para a[j] 18: 00070793 addi a5, a4, 0 # j = i Laço interno: 1c: ffc62883 lw a7, -4(a2) # a7 = a[j-1] 20: 01185a63 bge a6, a7, 34 # se

usando s1tu para calcular el acarreo de salida: add a0, a2, a4 # sumar la parte baja (32 bits): a0 = a2 + a4 sltu a2, a0, a2 # a2' = 1 if (a2 + a4) < a2, a2' = 0 else add a5, a3, a5 # sumar la parte RVC) # a1 es n, a3 apunta a a[0], a4 es i, a5 es j, a6 es x 0: 00450693 addi a3,a0,4 # a3 apunta a a[i] 4: 00100713 addi a4,x0,1 # i = 1 Outer Loop: 8: 00b76463 bltu a4,a1,10 # si i < n, saltar a Continue 10: 0006a803 lw a6,0(a3) # x = a[i] 14: 00068613 addi a2,a3,0 # a2 apunta a a[j] 18: 00070793 addi a5,a4,0 # j = i Inner Loop: 1c: ffc62883 lw a7,-4(a2) # a7 = a[j-1] 20: 01185a63 bge a6,a7,34 # si a[j-1]

3;}} $$ $$ b6=\T5\%1000; $$ $$ \mathrm{T7}=\mathrm{a4}+\mathrm{b6}; $$ return $T7; { //$a1: [ANY], $b2: [ANY] //$T3: [LONG, DOUBLE] //$a4: [LONG] //$T5: [LONG, DOUBLE] //$b6: [LONG] //$T7: [LONG * 3; $$ $$ b6=\T5\%1000; $$ $$ \text{T7} = \text{a4} + \text{b6}; $$ return $T7; //$a1: [ANY], $b2: [ANY] //$T3: [LONG, DOUBLE] //$a4: [LONG] //$T5: [LONG, DOUBLE] //$b6: [LONG] / ZEND ADD = $a1 * 2; //a1： $$ ANY $$ ，b2： $$ ANY $$ //$T3: [LONG, DOUBLE] $a4 = $T3 % 1000; $$ \mathrm{T5}=\mathrm{b2}\ast3; $$ //$a4: [LONG] //$T5: [LONG, DOUBLE] //$b6: [LONG] mov 0x50(\%r14), \%rax

loop、loope、loopz、loopne、loopnz。 ## ■补充说明：无需条件码的多字加法 RV32I 通过 sltu 计算进位: add a0, a2, a4 # 低 32 位相加: a0 = a2 + a4 sltu a2, a0, a2 # 若 (a2 + a4) < a2, 则 a2' = 1, 否则 a2' = 0 add a5, a3, a5 # 高 32 位相加: a5 = RVC 则 52 字节) # a1 是变量 n，a3 指向 a[0]，a4 是变量 i，a5 是变量 j，a6 是变量 x 0: 00450693 addi a3, a0, 4 # a3 指向 a[i] 4: 00100713 addi a4, x0, 1 # i = 1 Outer Loop: 8: 00b76463 bltu a4, a1, 10 # 若 i < n，跳到 Continue 10: 0006a803 lw a6, 0(a3) # x = a[i] 14: 00068613 addi a2, a3, 0 # a2 指向 a[j] 18: 00070793 addi a5, a4, 0 # j = i Inner Loop: 1c: ffc62883 lw a7, -4(a2) # a7 = a[j-1] 20: 01185a63 bge a6, a7, 34 # 若 a[j-1]

a1|Function argument, return value| |x12 / a2|Function argument| |x13 / a3|Function argument| |x14 / a4|Function argument| |x15 / a5|Function argument| |x16 / a6|Function argument| |x17 / a7|Function argument| ## ■고난도: 조건 코드 없는 멀티워드 덧셈 캐리-아웃을 계산하기 위해 s1tu를 사용하여 RV32I에서 다음과 같이 수행된다. add a0,a2,a4 # 하위 32비트 덧셈: a0 = a2 + a4 sltu a2,a0,a2 # 만약 (a2+a4) < a2이면 a2' = 1, 그렇지 않으면 a2' = 0 add a5,a3,a5 # 상위 a1 is n, a3 points to a[0], a4 is i, a5 is j, a6 is x 0: 00450693 addi a3, a0, 4 # a3 is pointer to a[i] 4: 00100713 addi a4, x0, 1 # i = 1 Outer Loop: 8: 00b76463 bltu a4, a1, 10 # if i < n, jump

blication:> >>> a4 = Article(headline='NASA finds intelligent life on Earth') >>> a4.save() >>> p2.article_set.add(a4) >>> p2.article_set.all() And you can clear from the other end: >>> p2.article_set.add(a4, a5) >>> p2.article_set.all() A4%A5%A6%A7%A8%A9%A10%A2%A3%A4%A5%A6%A7%A8%A9%A10%A2%A3%A4%A5%A6%A7%A8%A9%A10%A2%A3%A4%A5%A6%A7%A8%A9%A10%A2%A3%A4%A5%A6%A7%A8%A9%A10%A2%A3%A4%A5%A6%A7%A8%A9%A10%A2%A3%A4%A5%A6%A7%A8%A9